Solution Graph The Equation Y 2x 0 And X 2y 0 Where Do These Graphs Intersect
so x = −(y2 − 2y 1 −1) = −(y2 −2y 1) 1 Therefore, The coefficient of the square term is negative, so the parabola opens in the negative direction For a horizontal parabola, this means it opens to the left The axis of symmetry is the line y = 1 And if we start at the vertex (1,1) and go ±1 in the y direction (vertically), the From the given equation #x^2y^22x3=0# perform completing the square method to determine if its a circle, ellipse, hyperbola There are 2 second degree terms so we are sure it is not parabola #x^2y^22x3=0# #x^22xy^2=3# add 1 to both sides of the equation #x^22x1y^2=31# #(x^22x1)y^2=4# #(x1)^2(y0)^2=2^2# it takes the form #(x
